In hydrogen atom, the electron is moving round the nucleus with velocity 2.18×106 m/s in an orbit of radius of radius 0.528 Ao. The acceleration of the electron is:

acentripetal=v2r=2.18x10620.528x10-10≃9x1022m/s2

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18×106 m/s in an orbit of radius of radius 0.528 Ao. The acceleration of the electron is:

acentripetal=v2r=2.18x10620.528x10-10≃9x1022m/s2

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In hydrogen atom, the electron is moving round the nucleus with velocity 2.18×10⁶ m/s in an orbit of radius of radius 0.528 $\overset{o}{A}$ . The acceleration of the electron is:

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9×10¹⁸m/s²

9×10²² m/s²

9×10^–22 m/s²

9×10¹² m/s²

answer is B.

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$a_{centripetal} = \frac{v^{2}}{r} = \frac{{(2.18 x 10^{6})}^{2}}{0.528 x 10^{- 10}} ≃ 9 x 10^{22} m / s^{2}$

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In hydrogen atom, the electron is moving round the nucleus with velocity 2.18×106 m/s in an orbit of radius of radius 0.528 Ao. The acceleration of the electron is:

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In hydrogen atom, the electron is moving round the nucleus with velocity 2.18×10⁶ m/s in an orbit of radius of radius 0.528 $\overset{o}{A}$ . The acceleration of the electron is: