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Q.

In hydrogen spectrum the shortest wave length of Lyman & Balmer series are  λ1&λ2   respectively the rydberg constant of hydrogen is

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a

3(λ2λ1)4λ1λ2

b

2(λ2λ1)3λ1λ2

c

λ1+λ22

d

4(λ2λ1)3λ1λ2

answer is B.

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Detailed Solution

In hydrogen spectrum 
Short wave length of lyman series n1=1,n2=  
1λ1=R(112)=R1
In balmer series n1=2,n2=  
1λ2=R(122)=R4=R[34]
R=43[λ2λ1λ1λ2]
R=4(λ2λ1)3λ1λ2

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