Q.

In hydrogen spectrum, the shortest wavelength in the Balmer series is λ. The shortest wavelength in the Bracket series is

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a

2 λ

b

9 λ

c

4 λ

d

16 λ

answer is C.

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Detailed Solution

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Shortest wavelength is the maximum energy, i.e., transition from infinity to 2nd (Balmer series)
hcλ=13.6141=13.64
(For Brackett series, n=4)
hcλ1=13.61161=13.616
dividing the two λ1=4λ

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