In infinite dilutions, the equivalent conductance of ${\mathrm{Ba}}^{2+}$ and ${\mathrm{Cl}}^{-}$ are $127$and $76$ ${\mathrm{ohm}}^{-1}{\mathrm{cm}}^{-1}{\text{ eq}}^{-1}\text{.}$ The equivalent conductivity of ${\mathrm{BaCl}}_2$ at infinite dilution is

The value of equivalent conductance at infinite dilution for any electrolyte is the sum of the contribution of its constituent ions, i.e., anions and cations.

Chemical reaction of BaCl₂:

${\mathrm{BaCl}}_2\to {\mathrm{Ba}}^{2+}+2{\mathrm{Cl}}^{-}$
 

$$\begin{gathered} {\wedge }_{{\mathrm{BaCl}}_2}^{\circ }={\wedge }_{{\mathrm{Ba}}^{2+}}^{\circ }+2{\wedge }_{{\mathrm{Cl}}^{-}}^{\circ } \\ {\wedge }_{{\mathrm{BaCl}}_2}^{\circ }=127+2\times 76=279 {\mathrm{ohm}}^{-1} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1} \end{gathered}$$

$\mathrm{Equivalent} \mathrm{conductivity}=\frac{279}{2}=139.5 {\mathrm{ohm}}^{-1}{\mathrm{cm}}^{-1}{\mathrm{eq}}^{-1}$