In infinite dilutions, the equivalent conductance's of Ba2+ and Cl- are 127 and 76 ohm-1 cm-1 eqvt-1. The equivalent conductivity of BaCl2 at indefinite dilution is:

λ∞BaCl2=12λ∞Ba2++λCl ∞- =1272+76=139.5ohm-1 cm-1eq-1.

In infinite dilutions, the equivalent conductance's of Ba2+ and Cl- are 127 and 76 ohm-1 cm-1 eqvt-1. The equivalent conductivity of BaCl2 at indefinite dilution is:

λ∞BaCl2=12λ∞Ba2++λCl ∞- =1272+76=139.5ohm-1 cm-1eq-1.

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In infinite dilutions, the equivalent conductance's of Ba²⁺ and Cl^- are 127 and 76 ohm^-1 cm^-1 eqvt^-1. The equivalent conductivity of BaCl₂ at indefinite dilution is:

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101.5

139.5

203.5

279.5

answer is B.

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Detailed Solution

$λ^{\infty} {BaCl}_{2} = \frac{1}{2} λ^{\infty} {Ba}^{2 +} + λ {}^{\infty}{Cl}^{-} = \frac{127}{2} + 76 = 139.5 {ohm}^{- 1} {cm}^{- 1} {eq}^{- 1} .$

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In infinite dilutions, the equivalent conductance's of Ba2+ and Cl- are 127 and 76 ohm-1 cm-1 eqvt-1. The equivalent conductivity of BaCl2 at indefinite dilution is:

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In infinite dilutions, the equivalent conductance's of Ba²⁺ and Cl^- are 127 and 76 ohm^-1 cm^-1 eqvt^-1. The equivalent conductivity of BaCl₂ at indefinite dilution is: