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In Kjeldahl's method, 1.4 gm of an organic compound is strongly boiled with concentration NaOH. If the liberated ammonia gas is completely absorbed by 100 ml 0.1 M - $H_{2} {SO}_{4}$ solution and no acid is remained, the mass percent of nitrogen in he compound is :

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20%

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40%

80%

answer is A.

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Detailed Solution

$\underset{20}{2 {NH}_{3}} + \underset{10}{H_{2}} {SO}_{4} ⟶ {({NH}_{4})}_{2} {SO}_{4} + 2 H_{2} O (l)$

mm of N = 20

$= \frac{20}{1000} \times 14 = \frac{28}{100} = \frac{7}{25} gm$

% of N $= \frac{7}{25} \times \frac{1000}{14} = 20 %$

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