Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

In Kolbe’s electrolysis reaction of the salt of 2,2-dimethyl propanoic acid it gives the following major product at anode

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

Isobutene & isobutane

b

Hydrogen gas

c

Isoctane

d

2,2,3,3,-tetramethyl butane

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

Explanation:

In Kolbe’s electrolysis reaction, when a salt of 2,2-dimethylpropanoic acid (a carboxylate) undergoes electrolysis, the carboxylate anion (R-COO⁻) is oxidized at the anode to form a radical, which then undergoes a dimerization reaction to form a major product.

  • 2,2-Dimethylpropanoic acid has the structure (CH₃)₂C(CO₂⁻)CH₂, so the carboxylate ion is (CH₃)₂C(CO₂⁻)CH₂.
  • At the anode, the carboxylate anion undergoes oxidation, forming a radical that undergoes dimerization, leading to the formation of isobutene and isobutane (due to the coupling of two C₄ fragments).

Thus, Isobutene & isobutane are the major products formed at the anode in this electrolysis reaction.

Final Answer

The correct answer is: Isobutene & isobutane.

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon