Q.

In Kolbe’s electrolysis reaction of the salt of 2,2-dimethyl propanoic acid it gives the following major product at anode

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a

Isobutene & isobutane

b

Hydrogen gas

c

Isoctane

d

2,2,3,3,-tetramethyl butane

answer is C.

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Detailed Solution

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Explanation:

In Kolbe’s electrolysis reaction, when a salt of 2,2-dimethylpropanoic acid (a carboxylate) undergoes electrolysis, the carboxylate anion (R-COO⁻) is oxidized at the anode to form a radical, which then undergoes a dimerization reaction to form a major product.

  • 2,2-Dimethylpropanoic acid has the structure (CH₃)₂C(CO₂⁻)CH₂, so the carboxylate ion is (CH₃)₂C(CO₂⁻)CH₂.
  • At the anode, the carboxylate anion undergoes oxidation, forming a radical that undergoes dimerization, leading to the formation of isobutene and isobutane (due to the coupling of two C₄ fragments).

Thus, Isobutene & isobutane are the major products formed at the anode in this electrolysis reaction.

Final Answer

The correct answer is: Isobutene & isobutane.

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