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In L-C-R circuit f= $\frac{50}{π} H z$ , $V = 50 V$ and $R = 300 Ω$ . If L=1 H and C= 20 $μ$ C, then voltage across capacitor is

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Zero

20 V

30 V

50 V

answer is D.

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Detailed Solution

$Z = \sqrt{R^{2} + {(X_{L} - X_{C})}^{2}}$

$X_{L} = w L = 2 π ν L$

$X_{C} = \frac{1}{w c} = \frac{1}{2 π ν c}$

$Z = 500 Ω$

$I = \frac{V}{Z} = \frac{50}{500} = 0.1 A$

$V_{C} = I X_{C} = \frac{1}{2 π ν c}$

$= 50 V$

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