Q.

In Millikan's oil drop experiment, an oil drop of mass 16×10-6 kg is balanced by an electric field of 106V/m. The charge in coulomb on the drop, assuming g=10 m/s2 is

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a

16x 10-9C

b

6.2x 10-11C

c

16x 10-13C

d

16x 10-11C

answer is C.

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Detailed Solution

eE=mge=mgE=16×106×10106=16×1011C.

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