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Q.

In O₂ molecule, the correct order of energy of molecular orbitals is

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a

$σ_{2 s} < {σ_{2 s}}^{*}$

b

${σ_{2 s}}^{*} > {σ_{2 p_{x}}}^{*}$

c

$π_{2 p_{y}} > π_{2 p_{z}}$

d

$π_{2 p_{y}} = π_{2 p_{z}}$

answer is C.

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Detailed Solution

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$O_{2} : σ 1 s^{2} σ * 1 s^{2} σ 2 s^{2} σ * 2 s^{2} σ 2 p_{x}^{2} π 2 p_{y}^{2} π 2 p_{z}^{2} π * 2 p_{y}^{1} π * 2 p_{z}^{1} σ * 2 p_{x}^{0}$

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