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Q.

In one dimensional uniformly accelerated motion (acceleration =a ), find average velocity between from $t = 0 t o t = t .$

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a

$u + \frac{1}{3} a t$

b

$u + \frac{1}{2} a t$

c

$u + a t$

d

$u + \frac{1}{9} a t$

answer is C.

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Detailed Solution

$v = u + a t < v >_{0 - t} = \frac{\int_{0}^{t} (u + a t) d t}{t - 0} = u + \frac{1}{2} a t$

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In one dimensional uniformly accelerated motion (acceleration =a ), find average velocity between from t=0 to t= t.