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In order to determine the volume of blood in an animal, a 1.0 mL sample of solution of 10³ dpm of ,H³ is injected into the animal blood stream. After sufficient time for circulatory equilibrium to be established, 2 mL of blood is found to have
activity to 10 dpm. The volume of blood in animal is:

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199 mL

198 mL

200 mL

20 mL

answer is A.

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Detailed Solution

No change in activity of sample during establishment of circulatory equilibrium.

Let volume of blood is V mL, so total vol. = (V + l) mL after injection of sample.

2mL sample has activity of 10 dpm, so (V+ l) mL sample has activity of $\frac{10}{2} \times (V + 1)$ Since rate is constant so $\frac{10}{2} \times (V + 1) = 1000; V = 199 mL$

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