In order to prepare one litre normal solution of KMnO₄ , how many grams of KMnO₄ are required, if the solution is used in acidic medium for oxidation

One liter 1N solution of KMnO₄​ corresponds to 1 g equivalent. 

In acid medium for oxidation, the equivalent weight of KMnO₄​ is one fifth of its molecular mass. 

It is $\frac{158}{5}$​= 31.6 g.
Hence, 1 g equivalent of KMnO₄​ corresponds to 31.6 g.
Hence, in order to prepare one liter 1N solution of KMnO₄​, 31.6 grams of KMnO₄​ are required, if the solution to be used in acid medium for oxidation.