In order to prepare one litre normal solution of KMnO4 , how many grams of KMnO4 are required, if the solution is used in acidic medium for oxidation

One liter 1N solution of KMnO4 corresponds to 1 g equivalent. In acid medium for oxidation, the equivalent weight of KMnO4 is one fifth of its molecular mass. It is 1585= 31.6 g.Hence, 1 g equivalent of KMnO4 corresponds to 31.6 g.Hence, in order to prepare one liter 1N solution of KMnO4, 31.6 grams of KMnO4 are required, if the solution to be used in acid medium for oxidation.

In order to prepare one litre normal solution of KMnO4 , how many grams of KMnO4 are required, if the solution is used in acidic medium for oxidation

One liter 1N solution of KMnO4 corresponds to 1 g equivalent. In acid medium for oxidation, the equivalent weight of KMnO4 is one fifth of its molecular mass. It is 1585= 31.6 g.Hence, 1 g equivalent of KMnO4 corresponds to 31.6 g.Hence, in order to prepare one liter 1N solution of KMnO4, 31.6 grams of KMnO4 are required, if the solution to be used in acid medium for oxidation.

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In order to prepare one litre normal solution of KMnO₄ , how many grams of KMnO₄ are required, if the solution is used in acidic medium for oxidation

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158 g

31.6 g

790 g

62 g

answer is B.

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Detailed Solution

One liter 1N solution of KMnO₄ corresponds to 1 g equivalent.

In acid medium for oxidation, the equivalent weight of KMnO₄ is one fifth of its molecular mass.

It is $\frac{158}{5}$ = 31.6 g.
Hence, 1 g equivalent of KMnO₄ corresponds to 31.6 g.
Hence, in order to prepare one liter 1N solution of KMnO₄, 31.6 grams of KMnO₄ are required, if the solution to be used in acid medium for oxidation.

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