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Q.

In order to remove Mg2+ and Ca+2 from H2O, impure water is treated with sodium tripolyphosphate Na5P3O10 (MW = 368) where following sequential reactions takes place:

Na5P3O10+Mg+2Na3MgP3O10+2Na+Na3MgP3O10+Ca+2NaCaMgP3O10+2Na+

Select the correct statement about treatment of 10 L H2O having 48ppm ofMg+2and 40ppm of Ca+2.

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a

In order of remove all Mg+2 from H2O at least 7.36gm of Na5P3O10 is required

b

In order of remove all Mg+2 from H2O at least 3.68gm of Na5P3O10 is required

c

In order of remove all Mg+2 and Ca+2,7.36gm of Na5P3O10 is required

d

In order of remove all Mg+2and Ca+2 at least 11.04 gm of Na5P3O10 is required

answer is A, C.

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Detailed Solution

In the reaction we have,

Na5P3O10+Mg2+Na3MgP3O10+2Na+0.02 mole  0.4824 0.02 mole =7.36g
Na3MgP3O10+Ca2+NaCaMgM3O10+2Na+ 0.02 mole 0.4040 (Required, 0.01 mole)  =3.68g

So the option a and c is correct.

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