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In orthorhombic crystal system , the value of a, b and c are respectively $4.2 A^{0}, 8.6 A^{0}$ and $8.3 A^{0}$ . Given the molecular mass of the solute is 155 gm $m o l^{- 1}$ and that of density is 3.3 gm/cc, the number of formula units per unit cell is

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answer is C.

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Detailed Solution

$d = \frac{ZM}{N_{0} a^{3}}$ $(a^{3} = V = a \times b \times c)$

$Z = \frac{V \times N_{0} \times d}{M}$

$= \frac{4 .2 \times 8 .6 \times 8 .3 \times 10^{- 24} \times 6 .023 \times 10^{23} \times 3 .3}{155}$

$= 3 .84 ~ 4$

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