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In orthorhombic, the value of a, b and c are respectively 4.2 $\overset{o}{A}$ , 8.6 $\overset{o}{A}$ and 8.3 $\overset{o}{A}$ . given the molecular mass of the solute is 155 gm mol^-1 and that of density is 3.3 gm/cc, the number of formula units per unit cell is:

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answer is C.

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Detailed Solution

$Z = \frac{V \times N_{0} \times d}{M} = \frac{4 .2 \times 8 .6 \times 8 .3 \times 10^{- 24} \times 6 .023 \times 10^{23} \times 3 .3}{155} = 3 .84 = 4$

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