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Q.

In oscillating LC circuit, the total stored energy is U and maximum charge upon capacitor is Q. when the charge upon the capacitor is $\frac{Q}{2}$ , the energy stored in the inductor is:

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a

$\frac{4}{3} U$

b

$\frac{U}{4}$

c

$\frac{U}{2}$

d

$\frac{3 U}{4}$

answer is D.

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Detailed Solution

$U = \frac{Q^{2}}{2 C}$

When $q = \frac{Q}{2}, U = U_{Inductor} + \frac{(Q / 2)^{2}}{2 C}$

$U_{Inductor} = \frac{3}{4} U$

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