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Q.

In parallelogram ABCD the length of the diagonal AC is 8.75 cm and the distance of vertex B from AC is 7.5 cm. Find the area of parallelogram ABCD.

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a

68.98 c m^{2}

b

50.86 c m^{2}

c

32.81 c m^{2}

d

65.62 c m^{2}

answer is D.

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Detailed Solution

https://www.vedantu.com/question-sets/bdb0503e-e140-4494-818e-dc84fbda7b4420897825759610597.png

Area of ∆ ABC = Area of ∆ ACD

Area of ∆ ABC = \frac{1}{2} \times AC \times height

= \frac{1}{2} \times 8.75 \times 7.5

= 32.81 c m^{2}

∴ Area of parallelogram ABCD = Area of ∆ ABC + Area of ∆ ACD

= 32.81 + 32.81 = 65.62 c m^{2}

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