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Q.

In passing through a boundary from denser to rarer medium refraction will not take place if-

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a

light is incident normally on the boundary

b

the indices of refraction of the two media are same

c

the boundary is not visible if μ1=μ2

d

angle of incidence is  greater than sin-1(μR/μD)

answer is C, D.

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Detailed Solution

When light is incident normally on the boundary, then i=0, So, according to Snell's law μ1sin i=μ2 sin r, r is also zero, i.e., there is no refraction.

If μ1=μ2, then boundary will not be visible and r=i, i.e., there will be no refraction. If  i>sin-1(μR/μD) or i>ic(critical angle), then also there will be no refraction of light and light will be totally internally reflected.

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