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Q.

In photoelectric effect work function of any metal is 2.5 eV. The most energetic emitted electrons are stopped by the potential of 1.5 volt then

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a

Energy of incident photons is 4eV

b

Photoelectric current increases when we use photons of high frequency

c

None of the above

d

Energy of incident photons is 1 eV

answer is A.

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Detailed Solution

E=W+KEKE=EW=4eV

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In photoelectric effect work function of any metal is 2.5 eV. The most energetic emitted electrons are stopped by the potential of −1.5 volt then