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In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula $C_{6} H_{12} O_{6}$ .
How many grams of water would be required to produce 18 g of glucose? Compute the volume of water to be $1 {g cm}^{- 3}$ .

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108

1080

10.8

1.8

answer is A.

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Detailed Solution

$6 {CO}_{2} + 6 H_{2} O \to C_{6} H_{12} O_{6} + 6 O_{2}$

$108 g 180 g$

$? \leftarrow 18 g$

$10.8 g$

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