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In position A kinetic energy of a particle is 60 J and potential energy is -20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B

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Work done by conservative forces is $- 60 J$

Work done by external forces is $40 J$

Net work done by all the forces is $- 40 J$

Net work done by all the forces is $100 J$

answer is A.

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Detailed Solution

Work done by conservative forces $= U_{i} - U_{f} = - 20 - 40 = - 60 J$

Work done by external forces $= E_{f} - E_{i} = 140 - 40 = 100 J$

Work done by all the forces $= K_{f} - K_{i} = 100 - 60 = 40 J$

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