In [Pt(NH₃)₂Cl₂], Pt -Cl bond length is 2A^o and Cl - Cl distance is 2.88A^o then the compound is :

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Tetrahedral

Cis - Square planar

Square pyramidal

Trans -square planar

answer is C.

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Detailed Solution

The complex [Pt(NH₃)₂Cl₂], pt−Cl has square planar geometry.

The isomer will be trans if the distance between two chlorine atoms is twice the C-Cl bond length.

The isomer will be cis if the distance between two chlorine atoms is less than twice the C-Cl bond length. This is the case in the given complex as 2.8A^o<2×2A^o

Thus the given complex is cis square planar complex.

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