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Q.

In reaction(1), XeF6 hydrolysis to form HF and X. In reaction(2), XeF6 on partial hydro-lysis form HF, Y and Z. The products X, Y, Z respectively are

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a

XeO3, O2, XeO2F2

b

XeO3, Xe, XeO2F2

c

Xe, XeOF4, XeO2F2 

d

XeO3, XeOF4, XeO2F2

answer is B.

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Detailed Solution

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In reaction (1), XeF6 hydrolysis produces HF and X, which is xenon trioxide XeO3.

In reaction (2), XeF6 on partial hydrolysis forms HF, Y, and Z. The products Y and Z depend on the extent of hydrolysis. If XeF6 undergoes two partial hydrolysis reactions, the products are XeO2F2 (Y) and XeF4 (Z):

XeF6 + H2O → XeOF4 + 2HF

 XeOF4 + H2O → XeO2F2 + 2HF 

Therefore, the products X, Y, and Z are X: XeO3. Y: XeOF4 Z: XeO2F2

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In reaction(1), XeF6 hydrolysis to form HF and X. In reaction(2), XeF6 on partial hydro-lysis form HF, Y and Z. The products X, Y, Z respectively are