In reaction (1), $Xe{F}_6$ hydrolysis to form $HF$ and X. In reaction (2),  $Xe{F}_6$ on partial hydrolysis form $HF$. X, Y and Z are

For complete hydrolysis ${\mathrm{XeF}}_6$  has to react with three water molecules, for  

partial hydrolysis ${\mathrm{XeF}}_6$ has to react with two and one water molecule. Upon 

hydrolysis and

${\mathrm{XeF}}_6+3{\mathrm{H}}_2\mathrm{O}\to {\mathrm{XeO}}_3+6\mathrm{H}F$

${\mathrm{XeF}}_6+2{\mathrm{H}}_2\mathrm{O}\to {\mathrm{XeO}}_2{\mathrm{F}}_2+4\mathrm{HF}$

${\mathrm{XeF}}_6+{\mathrm{H}}_2\mathrm{O}\to {\mathrm{XeOF}}_4+2\mathrm{HF}$

From the above reactions of ${\mathrm{XeF}}_6$ with water molecules the products formed  are ${\mathrm{XeO}}_3$, ${\mathrm{XeOF}}_4$ and ${\mathrm{XeO}}_2{\mathrm{F}}_2$