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Q.

In series with 20 ohm resistor a 5 henry inductor is placed. To the combination an e.m.f. of 5 volt is applied. What will be the rate of increase of current at t = 0.25 sec

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a

e

b

e-2

c

e-1

d

None of these

answer is C.

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Detailed Solution

i = {i_0}(1 - {e^{ - Rt/L}}) Rightarrow frac{{di}}{{dt}} = {i_0}left( {frac{R}{L}} right),{e^{ - Rt/L}} = frac{E}{L}{e^{ - Rt/L}}
On putting values frac{{di}}{{dt}} = frac{1}{e} = {e^{ - 1}}

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