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Q.

In simple harmonic motion, when the displacement is minimum then 

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a

KE is maximum and PE is minimum

b

Both KE and PE are maximum

c

PE is maximum and KE is minimum

d

Both PE and KE are minimum

answer is A.

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Detailed Solution

Wkt,KE=12mω2A2y2

At mean position, displacement is minimum (y = 0)

            KE=12mω2A2max

and P.E=2π2mn2y

=0(minimum)

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