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In simulation of car accidents by an auto manufacturer, a car of mass 1000 kg moving with $18 k m h^{- 1}$ , collides with a horizontally mounted spring of spring constant $6250 N m^{- 1}$ .The maximum compression in the spring will be

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4 cm

2 m

2 cm

answer is B.

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Detailed Solution

$\frac{1}{2} {kx}^{2} = \frac{1}{2} m (v^{2} - 0)$

$x^{2} = \frac{1000 \times 10^{2}}{6250} = 4 \Rightarrow x = 2 m$

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