In single slit diffraction a = 0.14 mm, D = 2 m and distance of second dark band from central maxima is 1.6 cm. The wavelength of light is

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6500A⁰

7500 A⁰

5600 A⁰

8500 A⁰

answer is C.

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Detailed Solution

For dark band $a \frac{Y}{D} = nλ \Rightarrow λ = \frac{aY}{Dn}$
$= \frac{0 .14 \times 10^{- 3} \times 1 .6 \times 10^{- 2}}{2 \times 2} = 5600 A^{0}$

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