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Q.

In SN2, solvolysis of RX in which the solvent is a nucleophile, what is the order and molecularity of the reaction?

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a

First order; bimolecular

b

Pseudo first-order; bimolecular

c

Second order; bimolecular

d

First order; unimolecular

answer is D.

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Detailed Solution

SN2 solvolysis reaction is bimolecular and the rate law is:

Rate - K[RX][Solvent]
Since the concentration of the solvent is very large and exceeds the amount of RX, therefore, its concentration is constant. 

Hence the reaction will follow pseudo first-order rate law.

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In SN2, solvolysis of RX in which the solvent is a nucleophile, what is the order and molecularity of the reaction?