In steady state find the current through branch containing  the ideal inductor and voltage across capacitor.

 

at steady state inductor will be a conductor of zero resistance. so both the resistances of 2R will be short circuited  and total resistance of the circuit will be 2R and current is $\frac{E}{2R}$  potential across the capacitance is iR i.e, $\frac{E}{2}$