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In sum and difference method in vibration magnetometer, the time period is more if

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Both magnets are perpendicular to each other

Nothing can be said

Similar poles of both magnets are on same sides

Opposite poles of both magnets are on same sides

answer is B.

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Detailed Solution

In sum position: $T_{s} = 2 π \sqrt{\frac{I_{s}}{(M_{1} + M_{2}) B_{H}}}$

In difference position: $T_{d} = 2 π \sqrt{\frac{I_{d}}{(M_{1} - M_{2}) B_{H}}}$

It is clear that $T_{d} > T_{s} .$

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