In the above activity what is the maximum amount of  ${\mathrm{Na}}_2{\mathrm{SO}}_4$produced when 1 mole of NaCl react with 1 mole of ${\mathrm{H}}_2{\mathrm{SO}}_4$

$2{\mathrm{NaCl}}_{\left(\mathrm{s}\right)}+{\mathrm{H}}_2{\mathrm{SO}}_{4\left(\mathrm{l}\right)}\to 2\mathrm{HCl}+{\mathrm{Na}}_2{\mathrm{SO}}_{4\left(\mathrm{s}\right)}$
According to this reaction NaCl is limiting reagent 2 moles NaCl produce 1 mole ${\mathrm{Na}}_2{\mathrm{SO}}_4$, then 1 mole NaCl produce 0.5 moles of ${\mathrm{Na}}_2{\mathrm{SO}}_4$ i.e. 71 g of ${\mathrm{Na}}_2{\mathrm{SO}}_4$ mass is produced.