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Q.

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In the above reaction o/p ratio will be highest when :

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a

R=-CH3

b

R=-CH2 -CH3

c

R=-CHMe2

d

R=-CMe3

answer is A.

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Detailed Solution

The steric demand of H is, however, extremely small, and when attack on C6H5Y is by any other electrophile, E, which will necessarily be larger, there will be increasing interaction between E and Y in the transition state for attack at the position o- to Y (57 b, R = E) as attacking electrophile and substituent increase in size ; there can be no such interaction in the transition state for p- attack (57a, R = E). This will be reflected in an increasing G+ for o- attack, a consequently slower reaction, and the relative proportion of o- product will thus fall as the size of E and / or Y increase. This is illustrated by the falling fo/fp ratios which are observed for the nitration of alkylbenzenes (Y - CH3 → CMe3) under comparable conditions ;

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