In the adjoining circuit, the battery E₁ has an e.m.f. of 12 volts and zero internal resistance while the battery E₂has an emf of 2 volts. If the galvanometer G reads zero, then the value of the resistance X (in ohms) is:

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100

200

answer is B.

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Detailed Solution

As there is no current through galvanometer.

$\begin{array}{l} Hence V_{AB} = 2 V \\ 12 = 500 i + 2 \Rightarrow i = \frac{1}{50} amp \\ X \cdot \frac{1}{50} = 2 \Rightarrow X = 100 Ω \end{array}$

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