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Q.

In the adjoining figure, capacitors (1) and (2) have a capacitance C each. When the dielectric of dielectric constant K is inserted between the plates of one of the capacitor, the total charge flowing through battery is

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a

(K1)CE2(K+1) from C to D

b

KCEK+1from B to C

c

KCEK+1 from C to B

d

(K1)CE2(K+1) from B to C

answer is D.

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Detailed Solution

Initially, 

Q=C2E

After inserting the slab, 

Q'=KCCKC+CE=KCK+1E

Q'Q=KCEK+1CE2=(K1)CE2(K+1)

This charge is supplied by battery.

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