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Q.

In the adjoining figure, the circle meets the sides of an equilateral triangle at six points.
 

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If AG = 2, GF = 13, FC = 1 and HJ = 7, then DE equals to

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a

73

b

10

c

222

d

9

answer is A.

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Detailed Solution

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x+k+y=16Also  (t+7)×t=2×(2+13)⇒t=3now  x(x+k)=6×(6+7)and  y(y+k)=1×14
solving we get x=10−22,y=6−22 and k=222

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