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Q.

In the adjoining figure, two circles intersect at A and B. The centre of the smaller circle is O and lies on the circumference of the larger circle. If PAC and PBD are straight lines and APB=75o. Then, which of the following is the measure of AOB, ACB, ADB?


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a

150o,30o, 30o

b

150o, 30o, 60o

c

150o, 40o, 30o

d

120o, 30o, 30o  

answer is A.

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Detailed Solution

Consider the given figure,
Question ImageGiven that,
O is the center of the smaller circle.
APB=75.
We know that,
The angle subtended by an arc at the center of the circle has doubled the angle subtended at any point of the circle.
So,
AOB=2APB AOB=2×75
AOB=150 Now, since ACOB is a cyclic quadrilateral,
 ACB+AOB=180...[Opposite angles of a cyclic quadrilateral are supplementary]
 ACB+150=180  ACB=180-150  ACB=30 Also, since AOBD is a cyclic quadrilateral,
 ADB+AOB=180...[Opposite angles of cyclic quadrilateral are supplementary]
 ADB+150=180  ADB=180-150  ADB=30.
Hence, AOB=150, ACB=30and ADB=30.
Therefore, option 1 is correct.
 
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In the adjoining figure, two circles intersect at A and B. The centre of the smaller circle is O and lies on the circumference of the larger circle. If PAC and PBD are straight lines and ∠APB=75o. Then, which of the following is the measure of ∠AOB, ∠ACB, ∠ADB?