In the A.P; $10,7,4,\cdots ,-62$ , the 11^th term from the last is

$a=10,d=-3,n=16$

$T_{15}=10+\left(15-1\right)\left(-3\right)$

$=10+14\left(-3\right)$

$=10-42=-32$

$10,7,4,\cdots \cdots -50,-53,-56,-59,-62$

$-62-10+\left(n-1\right)\left(-3\right)$

$-62=10-3n+3$

$-62=13-3n\Rightarrow +75=+3n$

$n=$ 25^th term

1,2,3,4,5,6,7,8,9,10,11,12,13,14,(15)$\to$ 11^th

16,17,18,19,20,21,22,23,24,25