In the arrangement shown, charge on the capacitor at the steady state is 

If i be the current in the branch ACB, flowing from A to B, then 

$\mathrm{i}=\frac{10-2}{3+1} \mathrm{A}=2 \mathrm{A}$

$\therefore 10-{\mathrm{v}}_{\mathrm{c}}=3 \mathrm{x} 2\Rightarrow {\mathrm{v}}_{\mathrm{c}}=4 \mathrm{V}$

$\therefore$Charge $\mathrm{Q}=2\mathrm{\mu F} \mathrm{x} 4\mathrm{V}=8 \mathrm{\mu C}$