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Q.

In the arrangement shown in the figure, mass of the block B and A is 2m and m respectively. Surface between B and floor is smooth. The block B is connected to the block C by means of a string pulley system. If the whole system is released, then the minimum value of mass of block C so that block A remains stationary w.r.t. B. Coefficient of friction between A and B isμ    

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a

mμ1

b

2mμ1

c

3mμ1

d

4mμ1

answer is C.

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Detailed Solution

a=MCg3m+MC

f=mg

μN=mg

μma=mg

μa=g

ga=μ

(MC+3m)=MCga=MCμ

3m=MC(μ1)

MC=3mμ1

From free body diagram

MCgT=MCa

T=3ma_

MCg=(MC+3m)a

a=MCgMC+gm

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In the arrangement shown in the figure, mass of the block B and A is 2m and m respectively. Surface between B and floor is smooth. The block B is connected to the block C by means of a string pulley system. If the whole system is released, then the minimum value of mass of block C so that block A remains stationary w.r.t. B. Coefficient of friction between A and B isμ