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Q.

In the arrangement shown in the Fig., light of wavelength 6000A is incident on slits S1 and S2. Slits S3 and S4 have been opened such that S3 is the position of first maximum above the central maximum and S4 is the closest position where intensity is same as that of the light used, below the central maximum. The point O is equidistant from S1 and S2 and O' is equidistant from S3 and S4. The intensity light is I0.

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Find: the intensity of the brightest fringe.

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a

9I0

b

5I0

c

12I0

d

3I0

answer is B.

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Detailed Solution

For brightest fringe, phase difference=2nπ, n=0, ±1, ±2,....

Let I'' be the intensity of brightest fringe.

I''=I0+4I0+2I04I0cosϕ  (where cos ϕ=1) =9I0

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