Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

In the arrangement shown in the figure [sin 37° = 3/5]

Question Image

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

direction of force of friction is up the plane

b

the magnitude of force of friction is zero

c

the tension in the string is 20 N

d

magnitude of force of friction is 56 N

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Question Image

Net driving force = 60 - 40 = 20 N(down the plane)

As resisting force is greater than net driving force, the friction will be static of nature and friction force is 20 N (up the plane)

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
In the arrangement shown in the figure [sin 37° = 3/5]