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Q.

In the arrangement shown, mass of block A is 4 kg and the maximum mass of block B for which the system of blocks will be in equilibrium is 3 kg. What is the total reaction exerted by the table on block A?

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a

50 N

b

40 N

c

$40 \sqrt{2} N$

d

60 N

answer is A.

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Detailed Solution

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N = Normal reaction of the table on block A = 40 N

Frictional force on A, $f_{\max} = 30 N$

$∴ R = \sqrt{N^{2} + f_{\max}^{2}} = \sqrt{40^{2} + 30^{2}} N = 50 N$

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