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In the arrangement shown, the blocks are connected by a light string and they are placed on a frictionless horizontal surface. If the 4 kg block is pulled to the right by a force F, tension in the string is found to be 20 N. If the 2 kg block is pulled to the left by the same force F, tension in the string will be

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25 N

30 N

20 N

40 N

answer is D.

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Detailed Solution

In both cases acceleration (a) of the system will be the same. In the first case, $20 = 2 \times a$ and in the second case, $T = 4 \times a$

$∴ T = 4 \times \frac{20}{2} N = 40 N$

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