In the arrangement shown, the wedge of length 1 metre is pushed with an acceleration of $10 \sqrt{3} m / s^{2}$ . It is seen that block starts climbing up the smooth incline face of the wedge. find the time taken by the block to reach the top. $(g = 10 m / s^{2})$

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$\frac{3}{\sqrt{5}} \sec$

$\frac{4}{\sqrt{5}} \sec$

$\frac{1}{\sqrt{5}} \sec$

$\frac{2}{\sqrt{5}} \sec$

answer is A.

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$macos 30^{\circ} - m g \sin 30^{\circ} = m^{'}$

$a^{'} = 15 - 5 = 10 {ms}^{- 2}$

$S = \frac{1}{2} a^{'} t^{2}; 1 = \frac{1}{2} (10) (t^{2}); t = \frac{1}{\sqrt{5}} \sec$

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