In the below P-V diagram represents thermodynamic cycle of engine, operating with an ideal mono atomic gas. The amount of heat extracted from the source in single cycle is $\frac{x}{2} p_{0} v_{0}$ . Find $x$ value

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answer is 13.

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Detailed Solution

Heat supplied
$\begin{array}{l} Q = n C_{v} (2 T_{0} - T_{0}) + n C_{p} (2 T_{0} - T_{0}) \\ = n \times \frac{3 R}{2} \times \frac{P_{0} V_{0}}{n R} + n \times \frac{5 R}{2} (\frac{2 P_{0} V_{0}}{n R}) \\ = \frac{13}{2} P_{0} V_{0} \end{array}$

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