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Q.

In the biological process, the time taken by certain bacteria to double its population is called generation time. In milk at $37^{0} C$ bacteria has a generation time of 75 minutes. The population relative to the initial value at 60 minutes is $(\ln 2 = 0.7)$

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a

$e^{0.56}$

b

$e^{0.875}$

c

0.8

d

$e^{0.8}$

answer is A.

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Detailed Solution

$t = \frac{T_{g e n}}{\ln 2} . \ln \frac{A}{{[A]}_{0}} = \frac{75}{\ln 2} \ln \frac{A}{A_{0}} = 60 ∴ \frac{A}{A_{0}} = e^{0.56}$

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In the biological process, the time taken by certain bacteria to double its population is called generation time. In milk at 370C bacteria has a generation time of 75 minutes. The population relative to the initial value at 60 minutes is (ln2=0.7)