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Q.

In the Bohr model of hydrogen atom, the electron circles around the nucleus with a speed 5 × 105 m/s in an orbit of radius 5 × 10-11 m. The magnetic field at the centre of the orbit is [[1]] T.


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Detailed Solution

In the Bohr model of hydrogen atom, the electron circles around the nucleus with a speed 5 × 105 m/s in an orbit of radius 5 × 10-11 m. The magnetic field at the centre of the orbit is 3.2 T.
Given,
Radius of orbit, r= 5 × 10-11 m
Velocity of electron, v= 5 × 105 m/s We know that charge on electron, e=1.6 × 10-19 C
Magnetic field is the region in which an electric charge experiences magnetic influence. In a hydrogen atom, electrons are present carrying current and the atom will experience a magnetic field due to the charge.
The magnetic field at the centre of the atom is given by, B= μ0I2r
Also, we know that current, I= ev2πr
Where, e = charge on electron
v = velocity of electron
So, B= μ02r × ev2πr
      B= μ04π × evr2
      B= 10-7 × 1. 6× 10-19 ×5 × 105(5 × 10-11)2
      B= 1. 6× 10-21 ×5 (25 × 10-22)
      B= 165
      B=3.2 T.
 
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In the Bohr model of hydrogen atom, the electron circles around the nucleus with a speed 5 × 105 m/s in an orbit of radius 5 × 10-11 m. The magnetic field at the centre of the orbit is [[1]] T.