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Q.

In the Boolean algebra , $\bar{(\bar{A} . \bar{B})}$ . A equals to

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a

A

b

$\bar{A . B}$

c

$\bar{A + B}$

d

A+B

answer is B.

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Detailed Solution

$\bar{(\bar{A} . \bar{B})} . A = \bar{\bar{(A}} + \bar{\bar{B)}} . A = (A + B) . A$

= A.A + AB = A+AB = A(1+B) = A

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